Optimal. Leaf size=123 \[ \frac{2 d (c+d x) \sin ^3(a+b x)}{9 b^2}+\frac{4 d (c+d x) \sin (a+b x)}{3 b^2}-\frac{2 d^2 \cos ^3(a+b x)}{27 b^3}+\frac{14 d^2 \cos (a+b x)}{9 b^3}-\frac{2 (c+d x)^2 \cos (a+b x)}{3 b}-\frac{(c+d x)^2 \sin ^2(a+b x) \cos (a+b x)}{3 b} \]
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Rubi [A] time = 0.0960181, antiderivative size = 123, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {3311, 3296, 2638, 2633} \[ \frac{2 d (c+d x) \sin ^3(a+b x)}{9 b^2}+\frac{4 d (c+d x) \sin (a+b x)}{3 b^2}-\frac{2 d^2 \cos ^3(a+b x)}{27 b^3}+\frac{14 d^2 \cos (a+b x)}{9 b^3}-\frac{2 (c+d x)^2 \cos (a+b x)}{3 b}-\frac{(c+d x)^2 \sin ^2(a+b x) \cos (a+b x)}{3 b} \]
Antiderivative was successfully verified.
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Rule 3311
Rule 3296
Rule 2638
Rule 2633
Rubi steps
\begin{align*} \int (c+d x)^2 \sin ^3(a+b x) \, dx &=-\frac{(c+d x)^2 \cos (a+b x) \sin ^2(a+b x)}{3 b}+\frac{2 d (c+d x) \sin ^3(a+b x)}{9 b^2}+\frac{2}{3} \int (c+d x)^2 \sin (a+b x) \, dx-\frac{\left (2 d^2\right ) \int \sin ^3(a+b x) \, dx}{9 b^2}\\ &=-\frac{2 (c+d x)^2 \cos (a+b x)}{3 b}-\frac{(c+d x)^2 \cos (a+b x) \sin ^2(a+b x)}{3 b}+\frac{2 d (c+d x) \sin ^3(a+b x)}{9 b^2}+\frac{(4 d) \int (c+d x) \cos (a+b x) \, dx}{3 b}+\frac{\left (2 d^2\right ) \operatorname{Subst}\left (\int \left (1-x^2\right ) \, dx,x,\cos (a+b x)\right )}{9 b^3}\\ &=\frac{2 d^2 \cos (a+b x)}{9 b^3}-\frac{2 (c+d x)^2 \cos (a+b x)}{3 b}-\frac{2 d^2 \cos ^3(a+b x)}{27 b^3}+\frac{4 d (c+d x) \sin (a+b x)}{3 b^2}-\frac{(c+d x)^2 \cos (a+b x) \sin ^2(a+b x)}{3 b}+\frac{2 d (c+d x) \sin ^3(a+b x)}{9 b^2}-\frac{\left (4 d^2\right ) \int \sin (a+b x) \, dx}{3 b^2}\\ &=\frac{14 d^2 \cos (a+b x)}{9 b^3}-\frac{2 (c+d x)^2 \cos (a+b x)}{3 b}-\frac{2 d^2 \cos ^3(a+b x)}{27 b^3}+\frac{4 d (c+d x) \sin (a+b x)}{3 b^2}-\frac{(c+d x)^2 \cos (a+b x) \sin ^2(a+b x)}{3 b}+\frac{2 d (c+d x) \sin ^3(a+b x)}{9 b^2}\\ \end{align*}
Mathematica [A] time = 0.405903, size = 86, normalized size = 0.7 \[ \frac{-81 \cos (a+b x) \left (b^2 (c+d x)^2-2 d^2\right )+\cos (3 (a+b x)) \left (9 b^2 (c+d x)^2-2 d^2\right )-6 b d (c+d x) (\sin (3 (a+b x))-27 \sin (a+b x))}{108 b^3} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.007, size = 265, normalized size = 2.2 \begin{align*}{\frac{1}{b} \left ({\frac{{d}^{2}}{{b}^{2}} \left ( -{\frac{ \left ( bx+a \right ) ^{2} \left ( 2+ \left ( \sin \left ( bx+a \right ) \right ) ^{2} \right ) \cos \left ( bx+a \right ) }{3}}+{\frac{4\,\cos \left ( bx+a \right ) }{3}}+{\frac{ \left ( 4\,bx+4\,a \right ) \sin \left ( bx+a \right ) }{3}}+{\frac{ \left ( 2\,bx+2\,a \right ) \left ( \sin \left ( bx+a \right ) \right ) ^{3}}{9}}+{\frac{ \left ( 4+2\, \left ( \sin \left ( bx+a \right ) \right ) ^{2} \right ) \cos \left ( bx+a \right ) }{27}} \right ) }-2\,{\frac{a{d}^{2} \left ( -1/3\, \left ( bx+a \right ) \left ( 2+ \left ( \sin \left ( bx+a \right ) \right ) ^{2} \right ) \cos \left ( bx+a \right ) +1/9\, \left ( \sin \left ( bx+a \right ) \right ) ^{3}+2/3\,\sin \left ( bx+a \right ) \right ) }{{b}^{2}}}+2\,{\frac{cd \left ( -1/3\, \left ( bx+a \right ) \left ( 2+ \left ( \sin \left ( bx+a \right ) \right ) ^{2} \right ) \cos \left ( bx+a \right ) +1/9\, \left ( \sin \left ( bx+a \right ) \right ) ^{3}+2/3\,\sin \left ( bx+a \right ) \right ) }{b}}-{\frac{{a}^{2}{d}^{2} \left ( 2+ \left ( \sin \left ( bx+a \right ) \right ) ^{2} \right ) \cos \left ( bx+a \right ) }{3\,{b}^{2}}}+{\frac{2\,acd \left ( 2+ \left ( \sin \left ( bx+a \right ) \right ) ^{2} \right ) \cos \left ( bx+a \right ) }{3\,b}}-{\frac{{c}^{2} \left ( 2+ \left ( \sin \left ( bx+a \right ) \right ) ^{2} \right ) \cos \left ( bx+a \right ) }{3}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.07171, size = 365, normalized size = 2.97 \begin{align*} \frac{36 \,{\left (\cos \left (b x + a\right )^{3} - 3 \, \cos \left (b x + a\right )\right )} c^{2} - \frac{72 \,{\left (\cos \left (b x + a\right )^{3} - 3 \, \cos \left (b x + a\right )\right )} a c d}{b} + \frac{36 \,{\left (\cos \left (b x + a\right )^{3} - 3 \, \cos \left (b x + a\right )\right )} a^{2} d^{2}}{b^{2}} + \frac{6 \,{\left (3 \,{\left (b x + a\right )} \cos \left (3 \, b x + 3 \, a\right ) - 27 \,{\left (b x + a\right )} \cos \left (b x + a\right ) - \sin \left (3 \, b x + 3 \, a\right ) + 27 \, \sin \left (b x + a\right )\right )} c d}{b} - \frac{6 \,{\left (3 \,{\left (b x + a\right )} \cos \left (3 \, b x + 3 \, a\right ) - 27 \,{\left (b x + a\right )} \cos \left (b x + a\right ) - \sin \left (3 \, b x + 3 \, a\right ) + 27 \, \sin \left (b x + a\right )\right )} a d^{2}}{b^{2}} + \frac{{\left ({\left (9 \,{\left (b x + a\right )}^{2} - 2\right )} \cos \left (3 \, b x + 3 \, a\right ) - 81 \,{\left ({\left (b x + a\right )}^{2} - 2\right )} \cos \left (b x + a\right ) - 6 \,{\left (b x + a\right )} \sin \left (3 \, b x + 3 \, a\right ) + 162 \,{\left (b x + a\right )} \sin \left (b x + a\right )\right )} d^{2}}{b^{2}}}{108 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.63428, size = 298, normalized size = 2.42 \begin{align*} \frac{{\left (9 \, b^{2} d^{2} x^{2} + 18 \, b^{2} c d x + 9 \, b^{2} c^{2} - 2 \, d^{2}\right )} \cos \left (b x + a\right )^{3} - 3 \,{\left (9 \, b^{2} d^{2} x^{2} + 18 \, b^{2} c d x + 9 \, b^{2} c^{2} - 14 \, d^{2}\right )} \cos \left (b x + a\right ) + 6 \,{\left (7 \, b d^{2} x + 7 \, b c d -{\left (b d^{2} x + b c d\right )} \cos \left (b x + a\right )^{2}\right )} \sin \left (b x + a\right )}{27 \, b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 2.5926, size = 284, normalized size = 2.31 \begin{align*} \begin{cases} - \frac{c^{2} \sin ^{2}{\left (a + b x \right )} \cos{\left (a + b x \right )}}{b} - \frac{2 c^{2} \cos ^{3}{\left (a + b x \right )}}{3 b} - \frac{2 c d x \sin ^{2}{\left (a + b x \right )} \cos{\left (a + b x \right )}}{b} - \frac{4 c d x \cos ^{3}{\left (a + b x \right )}}{3 b} - \frac{d^{2} x^{2} \sin ^{2}{\left (a + b x \right )} \cos{\left (a + b x \right )}}{b} - \frac{2 d^{2} x^{2} \cos ^{3}{\left (a + b x \right )}}{3 b} + \frac{14 c d \sin ^{3}{\left (a + b x \right )}}{9 b^{2}} + \frac{4 c d \sin{\left (a + b x \right )} \cos ^{2}{\left (a + b x \right )}}{3 b^{2}} + \frac{14 d^{2} x \sin ^{3}{\left (a + b x \right )}}{9 b^{2}} + \frac{4 d^{2} x \sin{\left (a + b x \right )} \cos ^{2}{\left (a + b x \right )}}{3 b^{2}} + \frac{14 d^{2} \sin ^{2}{\left (a + b x \right )} \cos{\left (a + b x \right )}}{9 b^{3}} + \frac{40 d^{2} \cos ^{3}{\left (a + b x \right )}}{27 b^{3}} & \text{for}\: b \neq 0 \\\left (c^{2} x + c d x^{2} + \frac{d^{2} x^{3}}{3}\right ) \sin ^{3}{\left (a \right )} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.13405, size = 185, normalized size = 1.5 \begin{align*} \frac{{\left (9 \, b^{2} d^{2} x^{2} + 18 \, b^{2} c d x + 9 \, b^{2} c^{2} - 2 \, d^{2}\right )} \cos \left (3 \, b x + 3 \, a\right )}{108 \, b^{3}} - \frac{3 \,{\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + b^{2} c^{2} - 2 \, d^{2}\right )} \cos \left (b x + a\right )}{4 \, b^{3}} - \frac{{\left (b d^{2} x + b c d\right )} \sin \left (3 \, b x + 3 \, a\right )}{18 \, b^{3}} + \frac{3 \,{\left (b d^{2} x + b c d\right )} \sin \left (b x + a\right )}{2 \, b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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